How you will behaue youre selfe with the Astralabe.

Now you hauing your Astralabe, if you doe require to know how many degrees the pole artick is aboue your horizon, take your Astralabe and hange it vpon one of your fingers, and lift vp or put down the athladaie or rule with y^e sightes till y^e beames of the Sunne doth pearse both the sightes of the rule or atheladaye, the Sunne beames geuing shadowe through both the sightes,

then looke in the table what declination the sunne hath, whether that the declination be towardes the south of the equinoctiall or towardes the north of it, then loke vpon your astralabe what altitude the Sûne hath vpon the meridian vpon that daye of the moneth in your table,

then if that it hath north declinatiô subtract, or pull away your declination, if south declination, adde or put to your delination to the altitude of height of the Sunne, then that doth shew you the true equinoctiall:

then when you haue the true height of the equinoctiall, looke how many degrees that cometh vnto, subtract or pull that sum out of 90. degrees, which degrees & minutes, then that doth remaine shalbe the height of the pole aboue your horizon.

For this you must côsider, that from the zeneth or prick ouer the crowine of your head to be .90. degrees downe to the horizon, then looke what height the equinoctiall is from the horizon, so much is the zeneth from the pole, the must it nedes be said that that is the altitude of the pole to be iust the distaunce of the zeneth downe to the equinoctiall.

As for an exaple, this at Grauesende the yeare .1566. I take the Sunne vpon the meridian the .10. daie of Aprill, & founde the altitude of the Sunne lifted aboue the horizon .49. degrees 49. minutes,

then I toke the Sunne the next daie and founde the Sunne vpon the meridian .50. degrees .9. min. so I found the declinatio of the sunne more the .11. daie then it was the .10. daie by .21. mi.

which signifieth to me that the Sunne entred into the first min. of Taurus, at one of the clocke after midnight.

The .x. dale of Aprill, the sunne hauing north declination of the equinoctiall, and the declination ii. degrees .40. mi.

Upon the .11. daie of the moneth, then I pulled ye declinatiô .11. degrees 40. mi. out Of .50. degrees .9. mi. the remainer was 38. degrees .29. mi. The altitude or height of the equinoctiall aboue the horizon:

nowe I doe take or subtract .38. degrees. 29 mi. out of 90. degrees, the remainer is the height of y^e pole, being .51. degrees 31. mi. So in like case it is from the zeneth to the pole .38. degrees .29. min. & from the pole downe to the horizon .51. degrees .31. mi. as by the example of this figure.